Consider the reaction represented by the equation.

2NaHCO3(s) → 2Na2CO 3(S) + CO 2(g) + H2O(g)

What volume of carbon (IV)oxide at s.t.p is evolved when 0. 5 moles of NaHCO3 is heated? [Molar volume = 22.4 dm³ at s.t. p]

A. 1.12 dm³
B. 2.24 dm³
C. 5.6 dm³
D. 56.0 dm³

Correct Answer: Option C

C. 5.6 dm³

Explanation

2NaHCO3(s) → 2Na2CO 3(S) + CO 2(g) + H2O(g)

2 moles of 2NaHCO3(s) produces 22.4 dm³ of CO2

0.5 moles of 2NaHCO3 will produce 0.5×22.4/2

= 11.2/2

= 5.6 dm³