What is the oxidation number of chromium in K2CrO4?

A. +1

B. +2

C. +4

D. +6

Correct Answer: Option D

**D. +6**

Explanation

K2CrO4 (O.N of K) X 2 + O.N of Cr + (O.N of oxygen) X 4 = 0

1 X 2 + X + -2 X 4 = 0

2 + x + -8 = 0

2 + x – 8 = 0

x = 8 – 2 = + 6

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