The number of oxygen molecules present in 16.0g of the gas is ______?

[Avogadro’s number = 6.02 x 10^23]

A. 6.02 x 10^22
B. 6.02 x 10^23
C. 3.01 x 10^23
D. 1.51 x 10^23

Correct Answer: Option C

C. 3.01 x 10^23

Explanation

1 mole = Molar mass of gas = Avogadros number

32g of O2 = 6.02 x 1023

16g of O2 = x
x = 16×6.02×10^23/32 = 3.01 x 1023