Consider the following equation; Cr2O7(aq)²- + 14H+(aq) + 6e- → 2Cr³+(aq) + 7H2O(I). The oxidation number of chromium changes from

A. -2 to + 3
B. – 2 to + 6
C. + 6 to + 3
D. + 7 to + 6

Correct Answer: Option C

C. + 6 to + 3