An alternating current with a peak value of 5A passes through a resistor of resistance 10Ω. Calculate the rate at which energy is dissipated in the resistor

A. 250W
B. 125W
C. 50W
D. 35.4W
E. 12.5W

Correct Answer: Option A

A. 250W

Explanation
P=I^2R = 25×10=250W